Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Zudem | 1141 | 72 | 1 | 72.0000 |
Der | 18705 | 1229 | 26 | 47.2692 |
Insgesamt | 541 | 46 | 1 | 46.0000 |
Außerdem | 801 | 46 | 1 | 46.0000 |
Dazu | 699 | 45 | 1 | 45.0000 |
Die | 33984 | 1869 | 42 | 44.5000 |
Dabei | 1446 | 86 | 2 | 43.0000 |
Im | 5265 | 282 | 7 | 40.2857 |
Sein | 580 | 37 | 1 | 37.0000 |
Dennoch | 399 | 33 | 1 | 33.0000 |
Doch | 2643 | 98 | 3 | 32.6667 |
Zwar | 425 | 30 | 1 | 30.0000 |
«Ich | 342 | 28 | 1 | 28.0000 |
sondern | 2572 | 54 | 2 | 27.0000 |
Danach | 344 | 27 | 1 | 27.0000 |
Ein | 4407 | 269 | 10 | 26.9000 |
Denn | 1580 | 79 | 3 | 26.3333 |
Das | 15539 | 680 | 26 | 26.1538 |
Bereits | 532 | 26 | 1 | 26.0000 |
Dies | 1043 | 77 | 3 | 25.6667 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
worden | 3638 | 15 | 328 | 0.0457 |
mitteilte | 469 | 2 | 31 | 0.0645 |
Spielzeit | 139 | 1 | 13 | 0.0769 |
Wall | 197 | 1 | 13 | 0.0769 |
jeweiligen | 182 | 1 | 12 | 0.0833 |
diejenigen | 118 | 1 | 12 | 0.0833 |
reine | 109 | 1 | 11 | 0.0909 |
jährlichen | 84 | 1 | 10 | 0.1000 |
Umstand | 63 | 1 | 10 | 0.1000 |
bestehenden | 130 | 1 | 10 | 0.1000 |
erfolgreichen | 151 | 1 | 9 | 0.1111 |
darauf hin | 158 | 1 | 9 | 0.1111 |
städtischen | 87 | 1 | 9 | 0.1111 |
Tage lang | 62 | 1 | 9 | 0.1111 |
Milliarden | 1857 | 17 | 138 | 0.1232 |
Konkurrenten | 222 | 2 | 16 | 0.1250 |
tollen | 87 | 1 | 8 | 0.1250 |
sämtliche | 156 | 1 | 8 | 0.1250 |
Dortmunder | 99 | 1 | 8 | 0.1250 |
Bundesländern | 102 | 1 | 8 | 0.1250 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II